Logarithms Part I
Intro to logarithms
$ \begin{aligned}
y &= a^x \\
log_{a} y &= log_{a} a^x \\
log_{a} y &= x\\
\end{aligned}$
y, $\ a^x $ is known as the argument
a is known as the base
x is known as the exponent or the power
It is important to recognize that the base of the argument (a) equals to the base of the log (a)
Example 1
$ \begin{aligned}
y &= a^x \\
3 &= 10^x\\
log_{10} 3 &= log_{10} 10^x \\
log_{10} 3 &= x\\
\end{aligned}$
Example 2
$ \begin{aligned}
5 &= e^x\\
log_{e} 5 &= log_{e} e^x \\
log_{e} 5 &= x\\
x &= 1.61 \quad \text{to 3 s.f.}
\end{aligned}$
The next example will show you how Taking log on both sides can help you to answer questions
Example 3
Solve $ 10^{2x} - 2 ( 10^{x} ) -3 =0 $
We start by using the Substitution $ A = 10^x $
$\begin{aligned}
A^2 - 2A - 3 = 0 \\
(A - 3) ( A + 1) = 0 \\
A = 3 \qquad A = -1 \\
\text{Recall that } A = 10^x \\
10^x = 3 \quad 10^x = -1 \\
10^x \neq -1 \\
\text{hence we reject } 10^x = -1 \\
10^x = 3 \\
\text{ taking log on both sides } \\
\log_{10} 10^x = \log_{10} 3 \\
\text{ use calculator to evaluate } \log_{10} 3 \\
x = 0.477 \\
\end{aligned} $
Logarithms Part II will illustrate how we can use the "Taking log on both sides" technique in practical situations
$ \begin{aligned}
y &= a^x \\
log_{a} y &= log_{a} a^x \\
log_{a} y &= x\\
\end{aligned}$
y, $\ a^x $ is known as the argument
a is known as the base
x is known as the exponent or the power
It is important to recognize that the base of the argument (a) equals to the base of the log (a)
Example 1
$ \begin{aligned}
y &= a^x \\
3 &= 10^x\\
log_{10} 3 &= log_{10} 10^x \\
log_{10} 3 &= x\\
\end{aligned}$
- log base 10 is commonly used as it can be evaluated using a calculator.
- In most cases, it is abbreviated as lg. $\ log_{10} $ is equivalent to $\ lg $.
- Another number that is commonly used is 2.718, commonly known as e.
- log base e (2.718) can also be evaluated using a calculator.
- $\ log_{e} $ is equivalent to $\ ln $.
Example 2
$ \begin{aligned}
5 &= e^x\\
log_{e} 5 &= log_{e} e^x \\
log_{e} 5 &= x\\
x &= 1.61 \quad \text{to 3 s.f.}
\end{aligned}$
The next example will show you how Taking log on both sides can help you to answer questions
Example 3
Solve $ 10^{2x} - 2 ( 10^{x} ) -3 =0 $
We start by using the Substitution $ A = 10^x $
$\begin{aligned}
A^2 - 2A - 3 = 0 \\
(A - 3) ( A + 1) = 0 \\
A = 3 \qquad A = -1 \\
\text{Recall that } A = 10^x \\
10^x = 3 \quad 10^x = -1 \\
10^x \neq -1 \\
\text{hence we reject } 10^x = -1 \\
10^x = 3 \\
\text{ taking log on both sides } \\
\log_{10} 10^x = \log_{10} 3 \\
\text{ use calculator to evaluate } \log_{10} 3 \\
x = 0.477 \\
\end{aligned} $
Logarithms Part II will illustrate how we can use the "Taking log on both sides" technique in practical situations
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